Obscure bug with locals not captured by function
This is a bug for the record. It exists because a compiled bytecode function captures only its globals, not its locals. The only way I can make the bug appear (ie the only time a function needs to know the locals it was compiled in context of) is using the builtin compile function, and execute pre compiled code within another module, as follows.
Put this in t1.py:
x = 1
import t2
c = compile('print(x)', 'me', 'exec')
t2.C().ex(c)
and this in t2.py:
x = 2
c = compile('print(x)', 'me2', 'exec')
class C:
x = 3
exec('print(x)')
exec(c)
def ex(self, c):
exec(c)
Then run micropython t1.py. Check against CPythons output.
The above code tests more than just this bug, in order that one can see exactly what contexts are used where.
Variables in functions do not exist in locals() - breaking exec
Possibly related to #2833
Found on Unix port
Declaring a variable in a function and printing locals() inside that function will not show the created variable, unlike CPython.
def test():
a = 42
print(locals())